Defining A Default Argument As A Global Variable
Solution 1:
A default variable is only evaluated and set once. So Python makes a copy of the reference and from then on, it always passes that reference as default value. No re-evaluation is done.
You can however solve this by using another object as default object, and then use an if
statement to substitute it accordingly. Something like:
the_default = object()
x = 1deffoo(a = the_default):
if a is the_default:
a = x
print a
x = 2
foo()
Note that we use is
to perform reference equality. So we check if it is indeed the default_object
. You should not use the the_default
object somewhere else in your code.
In many Python code, they use None
as a default (and thus reduce the number of objects the construct). For instance:
deffoo(a = None):
if a isNone:
a = x
print a
Note however that if you do that, your program cannot make a distinction between a user calling foo()
and foo(None)
whereas using something as the_object
makes it harder for a user to obtain a reference to that object. This can be useful if None
would be a valid candidate as well: if you want foo(None)
to print 'None'
and not x
.
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