Valueerror: Item Is Not In List
I am making this simple code: MyList=[] valueA=1 valueB=2 valueC=3 MyList.append (valueA) MyList.append (valueB) MyList.append (valueC) print (MyList) print ([MyList].index(valueB)
Solution 1:
[MyList] is a list consisting of a single item, which is MyList.
I don't know why you have wrapped MyList in another list. You need to call index on MyList itself:
print(MyList.index(valueB))
And the result will be 1, not 0, because valueB is the second item in MyList.
Solution 2:
Your mistake was that you put my_list into another anonymous list at the last line.It should be like this:
MyList=[]
valueA=1
valueB=2
valueC=3
MyList.append (valueA)
MyList.append (valueB)
MyList.append (valueC)
print (MyList)
print (MyList.index(valueB))
Output:
[1, 2, 3]
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