Removing Emojis From A String In Python

I found this code in Python for removing emojis but it is not working. Can you help with other codes or fix to this? I have observed all my emjois start with \xf but when I try to

Solution 1:

On Python 2, you have to use u'' literal to create a Unicode string. Also, you should pass re.UNICODE flag and convert your input data to Unicode (e.g., text = data.decode('utf-8')):

#!/usr/bin/env python
import re

text = u'This dog \U0001f602'
print(text) # with emoji

emoji_pattern = re.compile("["
        u"\U0001F600-\U0001F64F"  # emoticons
        u"\U0001F300-\U0001F5FF"  # symbols & pictographs
        u"\U0001F680-\U0001F6FF"  # transport & map symbols
        u"\U0001F1E0-\U0001F1FF"  # flags (iOS)
                           "]+", flags=re.UNICODE)
print(emoji_pattern.sub(r'', text)) # no emoji

Output

This dog 😂
This dog 

Note: emoji_pattern matches only some emoji (not all). See Which Characters are Emoji.

Solution 2:

I am updating my answer to this by @jfs because my previous answer failed to account for other Unicode standards such as Latin, Greek etc. StackOverFlow doesn't allow me to delete my previous answer hence I am updating it to match the most acceptable answer to the question.

#!/usr/bin/env python
import re

text = u'This is a smiley face \U0001f602'
print(text) # with emoji

def deEmojify(text):
    regrex_pattern = re.compile(pattern = "["
        u"\U0001F600-\U0001F64F"  # emoticons
        u"\U0001F300-\U0001F5FF"  # symbols & pictographs
        u"\U0001F680-\U0001F6FF"  # transport & map symbols
        u"\U0001F1E0-\U0001F1FF"  # flags (iOS)
                           "]+", flags = re.UNICODE)
    return regrex_pattern.sub(r'',text)

print(deEmojify(text))

This was my previous answer, do not use this.

def deEmojify(inputString):
    return inputString.encode('ascii', 'ignore').decode('ascii')

Solution 3:

Complete Version of remove Emojis
✍ 🌷 📌 👈🏻 🖥

import re
def remove_emojis(data):
    emoj = re.compile("["
        u"\U0001F600-\U0001F64F"  # emoticons
        u"\U0001F300-\U0001F5FF"  # symbols & pictographs
        u"\U0001F680-\U0001F6FF"  # transport & map symbols
        u"\U0001F1E0-\U0001F1FF"  # flags (iOS)
        u"\U00002500-\U00002BEF"  # chinese char
        u"\U00002702-\U000027B0"
        u"\U00002702-\U000027B0"
        u"\U000024C2-\U0001F251"
        u"\U0001f926-\U0001f937"
        u"\U00010000-\U0010ffff"
        u"\u2640-\u2642" 
        u"\u2600-\u2B55"
        u"\u200d"
        u"\u23cf"
        u"\u23e9"
        u"\u231a"
        u"\ufe0f"  # dingbats
        u"\u3030"
                      "]+", re.UNICODE)
    return re.sub(emoj, '', data)

Solution 4:

If you are not keen on using regex, the best solution could be using the emoji python package.

Here is a simple function to return emoji free text (thanks to this SO answer):

import emoji
def give_emoji_free_text(text):
    allchars = [str for str in text.decode('utf-8')]
    emoji_list = [c for c in allchars if c in emoji.UNICODE_EMOJI]
    clean_text = ' '.join([str for str in text.decode('utf-8').split() if not any(i in str for i in emoji_list)])
    return clean_text

If you are dealing with strings containing emojis, this is straightforward

>> s1 = "Hi 🤔 How is your 🙈 and 😌. Have a nice weekend 💕👭👙"
>> print s1
Hi 🤔 How is your 🙈 and 😌. Have a nice weekend 💕👭👙
>> print give_emoji_free_text(s1)
Hi How is your and Have a nice weekend

If you are dealing with unicode (as in the exmaple by @jfs), just encode it with utf-8.

>> s2 = u'This dog \U0001f602'
>> print s2
This dog 😂
>> print give_emoji_free_text(s2.encode('utf8'))
This dog

Edits

Based on the comment, it should be as easy as:

def give_emoji_free_text(text):
    return emoji.get_emoji_regexp().sub(r'', text.decode('utf8'))

Solution 5:

If you're using the example from the accepted answer and still getting "bad character range" errors, then you're probably using a narrow build (see this answer for more details). A reformatted version of the regex that seems to work is:

emoji_pattern = re.compile(
    u"(\ud83d[\ude00-\ude4f])|"  # emoticons
    u"(\ud83c[\udf00-\uffff])|"  # symbols & pictographs (1 of 2)
    u"(\ud83d[\u0000-\uddff])|"  # symbols & pictographs (2 of 2)
    u"(\ud83d[\ude80-\udeff])|"  # transport & map symbols
    u"(\ud83c[\udde0-\uddff])"  # flags (iOS)
    "+", flags=re.UNICODE)